What is the answer to 2ln(x+1)+1=0 ?

The answer to 2ln(x+1)+1=0 is x= 1/(sqrt(e))-1

Solve for x: 2ln(x+1)+1=0

The solution is x= 1/(sqrt(e))-1

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2 ln (x + 1) + 1 = 0

x = \frac{1}{e} - 1

Solution steps

2 ln (x + 1) + 1 = 0

Move

1

to the right side

2 ln (x + 1) = - 1

Divide both sides by

2

ln (x + 1) = - \frac{1}{2}

Apply log rules

x + 1 = \frac{1}{e}

Solve

x + 1 = \frac{1}{e} : x = \frac{1}{e} - 1

x = \frac{1}{e} - 1

Verify Solutions:

x = \frac{1}{e} - 1

True

The solution is

x = \frac{1}{e} - 1

lo g_{3} (8 x - 15) = 4

x^{2} y - 2 x y^{2} + ln (x) y = x y

lo g_{8} (a) = lo g_{2} (x), x > 0

lo g_{x} (3) = 0.4771

- 11090 = (- 8.3144) (923.15) ln (x)

What is the answer to 2ln(x+1)+1=0 ?
The answer to 2ln(x+1)+1=0 is x= 1/(sqrt(e))-1
Solve for x: 2ln(x+1)+1=0
The solution is x= 1/(sqrt(e))-1