What is the answer to solvefor x,7ln(2x+3)-40=9 ?

The answer to solvefor x,7ln(2x+3)-40=9 is x=(e^7-3)/2

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solvefor x,7ln(2x+3)-40=9

solve for

x, 7 ln (2 x + 3) - 40 = 9

x = \frac{e ^{7} - 3}{2}

Solution steps

7 ln (2 x + 3) - 40 = 9

Move

40

to the right side

7 ln (2 x + 3) = 49

Divide both sides by

7

ln (2 x + 3) = 7

Apply log rules

2 x + 3 = e^{7}

Solve

2 x + 3 = e^{7} : x = \frac{e ^{7} - 3}{2}

x = \frac{e ^{7} - 3}{2}

Verify Solutions:

x = \frac{e ^{7} - 3}{2}

True

The solution is

x = \frac{e ^{7} - 3}{2}

ln (x) + x = 2

2 lo g_{x} (2) + 4 lo g_{x} (4) = 5

\frac{x}{ln ( x )} = 1

6 ln (7 x - 8) + 8 = 50

\frac{1}{2} lo g_{2} (X) = - 3

What is the answer to solvefor x,7ln(2x+3)-40=9 ?
The answer to solvefor x,7ln(2x+3)-40=9 is x=(e^7-3)/2