What is the answer to solvefor b,log_{b}(2)=0.401 ?

The answer to solvefor b,log_{b}(2)=0.401 is b=4*2^{198/401}

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solvefor b,log_{b}(2)=0.401

solve for

b, lo g_{b} (2) = 0.401

b = 4 \cdot 2^{\frac{198}{401}}

Solution steps

lo g_{b} (2) = 0.401

Apply log rules

\frac{1}{lo g _{2} ( b )} = 0.401

Multiply both sides by

lo g_{2} (b)

\frac{1}{lo g _{2} ( b )} lo g_{2} (b) = 0.401 lo g_{2} (b)

Simplify

1 = 0.401 lo g_{2} (b)

Switch sides

0.401 lo g_{2} (b) = 1

Multiply both sides by

1000

401 lo g_{2} (b) = 1000

Divide both sides by

401

lo g_{2} (b) = \frac{1000}{401}

Apply log rules

b = 4 \cdot 2^{\frac{198}{401}}

Verify Solutions:

b = 4 \cdot 2^{\frac{198}{401}}

True

The solution is

b = 4 \cdot 2^{\frac{198}{401}}

4 ln (x - 5) = - 4

0.172 = 2 - lo g_{10} (x)

3 lo g_{3} (x - 1) = 3

x, lo g_{s} (x) = 4

x ln (x - 4) = 0

What is the answer to solvefor b,log_{b}(2)=0.401 ?
The answer to solvefor b,log_{b}(2)=0.401 is b=4*2^{198/401}