What is the answer to log_{3}(12x)-3=log_{2}(540) ?

The answer to log_{3}(12x)-3=log_{2}(540) is x=(3^{log_{2}(540)+2})/4

Solve for x: log_{3}(12x)-3=log_{2}(540)

The solution is x=(3^{log_{2}(540)+2})/4

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lo g_{3} (12 x) - 3 = lo g_{2} (540)

x = \frac{3 ^{l o g_{2} (540) + 2}}{4}

Solution steps

lo g_{3} (12 x) - 3 = lo g_{2} (540)

Move

3

to the right side

lo g_{3} (12 x) = lo g_{2} (540) + 3

Apply log rules

12 x = 3^{l o g_{2} (540) + 3}

Solve

12 x = 3^{l o g_{2} (540) + 3} : x = \frac{3 ^{l o g_{2} (540) + 2}}{4}

x = \frac{3 ^{l o g_{2} (540) + 2}}{4}

Verify Solutions:

x = \frac{3 ^{l o g_{2} (540) + 2}}{4}

True

The solution is

x = \frac{3 ^{l o g_{2} (540) + 2}}{4}

x = e^{l o g_{7} (x)}

y, ln (1 - y) = - k t

\frac{1}{64} = lo g_{8} (x)

1 = 2 lo g_{10} (x)

lo g_{10} (2 x) = lo g_{10} (6 x)

What is the answer to log_{3}(12x)-3=log_{2}(540) ?
The answer to log_{3}(12x)-3=log_{2}(540) is x=(3^{log_{2}(540)+2})/4
Solve for x: log_{3}(12x)-3=log_{2}(540)
The solution is x=(3^{log_{2}(540)+2})/4