What is the answer to log_{6}(((x+4))/(x-1))=1 ?

The answer to log_{6}(((x+4))/(x-1))=1 is x=2

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log_{6}(((x+4))/(x-1))=1

lo g_{6} (\frac{( x + 4 )}{x - 1}) = 1

x = 2

Solution steps

lo g_{6} (\frac{( x + 4 )}{x - 1}) = 1

Apply log rules

\frac{x + 4}{x - 1} = 6^{1}

Multiply both sides by

x - 1

\frac{x + 4}{x - 1} (x - 1) = 6^{1} (x - 1)

Simplify

x + 4 = 6 (x - 1)

Solve

x + 4 = 6 (x - 1) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

5 = lo g_{x} (\frac{1}{32})

lo g_{3} ((11 x + 30)^{4}) = 16

lo g_{23} (5 x - 1) = 2

2 lo g_{10} (5 x) = 6

2 ln (n) = ln (n^{2})

What is the answer to log_{6}(((x+4))/(x-1))=1 ?
The answer to log_{6}(((x+4))/(x-1))=1 is x=2
Solve for x: log_{6}(((x+4))/(x-1))=1
The solution is x=2