What are the solutions to the equation 9x^2-6x-4=-5 ?

The solutions to the equation 9x^2-6x-4=-5 are x= 1/3

Find the zeros of 9x^2-6x-4=-5

The zeros of 9x^2-6x-4=-5 are x= 1/3

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9 x^{2} - 6 x - 4 = - 5

x = \frac{1}{3}

Solution steps

9 x^{2} - 6 x - 4 = - 5

Move

5

to the left side

9 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

\frac{- 5 x ^{3} y}{15 x y ^{3}}

- 11 < 5 + 4 x

- (x + 3) + \frac{3}{4} x + 5 = 0

\frac{3}{8} + \frac{1}{5}

(x - 9)^{2} \geq 2 (x - 9)

What are the solutions to the equation 9x^2-6x-4=-5 ?
The solutions to the equation 9x^2-6x-4=-5 are x= 1/3
Find the zeros of 9x^2-6x-4=-5
The zeros of 9x^2-6x-4=-5 are x= 1/3