What is the answer to log_{3}(2x)=6+2log_{3}(x) ?

The answer to log_{3}(2x)=6+2log_{3}(x) is x= 2/729

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log_{3}(2x)=6+2log_{3}(x)

lo g_{3} (2 x) = 6 + 2 lo g_{3} (x)

x = \frac{2}{729}

Solution steps

lo g_{3} (2 x) = 6 + 2 lo g_{3} (x)

Apply log rules

x = \frac{2}{729}

Verify Solutions:

x = \frac{2}{729}

True

The solution is

x = \frac{2}{729}

lo g_{10} (x) = - 1.93

lo g_{243} (a) = lo g_{3} (x), a > 0

0.6 = lo g_{10} (y)

lo g_{5} (2 y - 7) = 0

- lo g_{10} (x) = 0.26

What is the answer to log_{3}(2x)=6+2log_{3}(x) ?
The answer to log_{3}(2x)=6+2log_{3}(x) is x= 2/729
Solve for x: log_{3}(2x)=6+2log_{3}(x)
The solution is x= 2/729