What is the answer to 9000=(4000)/(ln(x+10)) ?

The answer to 9000=(4000)/(ln(x+10)) is x=e^{4/9}-10

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9000=(4000)/(ln(x+10))

9000 = \frac{4000}{ln ( x + 10 )}

x = e^{\frac{4}{9}} - 10

Solution steps

9000 = \frac{4000}{ln ( x + 10 )}

Rewrite the equation with

ln (x + 10) = u

9000 = \frac{4000}{u}

Solve

9000 = \frac{4000}{u} : u = \frac{4}{9}

u = \frac{4}{9}

Substitute back

u = ln (x + 10),

solve for

x

Solve

ln (x + 10) = \frac{4}{9} : x = e^{\frac{4}{9}} - 10

x = e^{\frac{4}{9}} - 10

Verify Solutions:

x = e^{\frac{4}{9}} - 10

True

The solution is

x = e^{\frac{4}{9}} - 10

ln^{4} (x^{2}) = 16 ln (x)

lo g_{a} (x^{2}) = b

7 + lo g_{10} (x) = 10

5 ln (5 x - 9) + 11 = 26

lo g_{10} (x) = 1.8379

What is the answer to 9000=(4000)/(ln(x+10)) ?
The answer to 9000=(4000)/(ln(x+10)) is x=e^{4/9}-10
Solve for x: 9000=(4000)/(ln(x+10))
The solution is x=e^{4/9}-10