What is the answer to ln(x^4)+ln(x^2)=2 ?

The answer to ln(x^4)+ln(x^2)=2 is x=sqrt(e^{2/3)},x=-sqrt(e^{2/3)}

Solve for x: ln(x^4)+ln(x^2)=2

The solution is x=sqrt(e^{2/3)},x=-sqrt(e^{2/3)}

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ln (x^{4}) + ln (x^{2}) = 2

x = e^{\frac{2}{3}}, x = - e^{\frac{2}{3}}

Decimal Notation

x = 1.39561 \dots, x = - 1.39561 \dots

Solution steps

ln (x^{4}) + ln (x^{2}) = 2

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

x^{4} = (x^{2})^{2}

ln ((x^{2})^{2}) + ln (x^{2}) = 2

Apply log rules

x^{2} = e^{\frac{2}{3}}

Solve

x^{2} = e^{\frac{2}{3}} : x = e^{\frac{2}{3}}, x = - e^{\frac{2}{3}}

x = e^{\frac{2}{3}}, x = - e^{\frac{2}{3}}

Verify Solutions:

x = e^{\frac{2}{3}}

True

, x = - e^{\frac{2}{3}}

True

The solutions are

x = e^{\frac{2}{3}}, x = - e^{\frac{2}{3}}

2 ln (x - 2) = ln (x)

lo g_{6} (lo g_{4} (x)) = 0

ln (2 x) = 2.4

4 lo g_{10} (n) = n

x, ln (y - x^{2}) = 2

What is the answer to ln(x^4)+ln(x^2)=2 ?
The answer to ln(x^4)+ln(x^2)=2 is x=sqrt(e^{2/3)},x=-sqrt(e^{2/3)}
Solve for x: ln(x^4)+ln(x^2)=2
The solution is x=sqrt(e^{2/3)},x=-sqrt(e^{2/3)}