What is the answer to log_{10}(1)=log_{10}(2r-7) ?

The answer to log_{10}(1)=log_{10}(2r-7) is r=4

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log_{10}(1)=log_{10}(2r-7)

lo g_{10} (1) = lo g_{10} (2 r - 7)

r = 4

Solution steps

lo g_{10} (1) = lo g_{10} (2 r - 7)

Apply log rules

1 = 2 r - 7

Solve

1 = 2 r - 7 : r = 4

r = 4

Verify Solutions:

r = 4

True

The solution is

r = 4

lo g_{\frac{1}{2}} (x) = 0.01

0.54 = ln (x)

ln (y) = 0.3

lo g_{10} (\frac{x}{3}) = 1

lo g_{\frac{1}{2}} (a) = - 2

What is the answer to log_{10}(1)=log_{10}(2r-7) ?
The answer to log_{10}(1)=log_{10}(2r-7) is r=4
Solve for r: log_{10}(1)=log_{10}(2r-7)
The solution is r=4