What is the answer to 2ln(x+1)+3=0 ?

The answer to 2ln(x+1)+3=0 is x= 1/(e^{3/2)}-1

Solve for x: 2ln(x+1)+3=0

The solution is x= 1/(e^{3/2)}-1

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2 ln (x + 1) + 3 = 0

x = \frac{1}{e ^{\frac{3}{2}}} - 1

Decimal Notation

x = - 0.77686 \dots

Solution steps

2 ln (x + 1) + 3 = 0

Move

3

to the right side

2 ln (x + 1) = - 3

Divide both sides by

2

ln (x + 1) = - \frac{3}{2}

Apply log rules

x + 1 = \frac{1}{e ^{\frac{3}{2}}}

Solve

x + 1 = \frac{1}{e ^{\frac{3}{2}}} : x = \frac{1}{e ^{\frac{3}{2}}} - 1

x = \frac{1}{e ^{\frac{3}{2}}} - 1

Verify Solutions:

x = \frac{1}{e ^{\frac{3}{2}}} - 1

True

The solution is

x = \frac{1}{e ^{\frac{3}{2}}} - 1

lo g_{10} (x^{2}) = 5

y, 4 ln (y^{2}) = 8

2 ln (x - 1) - ln (2) = 2 ln (x)

x, lo g_{6} (x) = - 2

ln (x) + ln (x - 5) = ln (5 x)

What is the answer to 2ln(x+1)+3=0 ?
The answer to 2ln(x+1)+3=0 is x= 1/(e^{3/2)}-1
Solve for x: 2ln(x+1)+3=0
The solution is x= 1/(e^{3/2)}-1