What are the solutions to the equation 80+a^2=18a ?

The solutions to the equation 80+a^2=18a are a=10,a=8

Find the zeros of 80+a^2=18a

The zeros of 80+a^2=18a are a=10,a=8

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80 + a^{2} = 18 a

a = 10, a = 8

Solution steps

80 + a^{2} = 18 a

Move

18 a

to the left side

80 + a^{2} - 18 a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 18 a + 80 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 80 = 2

a_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 1}

a = \frac{- ( - 18 ) + 2}{2 \cdot 1} : 10

a = \frac{- ( - 18 ) - 2}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

a = 10, a = 8

7 x - 2 = 5 x + 14

4 x^{3} - 14 x

3 x = 14

8 - x \leq 5

\frac{2}{3} \cdot \frac{2}{3} \cdot \frac{2}{3}

What are the solutions to the equation 80+a^2=18a ?
The solutions to the equation 80+a^2=18a are a=10,a=8
Find the zeros of 80+a^2=18a
The zeros of 80+a^2=18a are a=10,a=8