What is the answer to log_{2}(x+16)+log_{2}(x+2)=8 ?

The answer to log_{2}(x+16)+log_{2}(x+2)=8 is x=-9+sqrt(305)

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log_{2}(x+16)+log_{2}(x+2)=8

lo g_{2} (x + 16) + lo g_{2} (x + 2) = 8

x = - 9 + 305

Decimal Notation

x = 8.46424 \dots

Solution steps

lo g_{2} (x + 16) + lo g_{2} (x + 2) = 8

Apply log rules

(x + 16) (x + 2) = 256

Solve

(x + 16) (x + 2) = 256 : x = - 9 + 305, x = - 9 - 305

x = - 9 + 305, x = - 9 - 305

Verify Solutions:

x = - 9 + 305

True

, x = - 9 - 305

False

The solution is

x = - 9 + 305

7 ln (2 x + 5) = 8

(ln (x)) (ln (x)) = 2 (ln (x))

lo g_{10} (3 x) = 0.85

lo g_{3} (3^{x^{2} - 2 x}) = 0

lo g_{10} (0.01 x) = - 3

What is the answer to log_{2}(x+16)+log_{2}(x+2)=8 ?
The answer to log_{2}(x+16)+log_{2}(x+2)=8 is x=-9+sqrt(305)
Solve for x: log_{2}(x+16)+log_{2}(x+2)=8
The solution is x=-9+sqrt(305)