What is the answer to 1+2log_{5}(x)=log_{5}(16x-3) ?

The answer to 1+2log_{5}(x)=log_{5}(16x-3) is x=3,x= 1/5

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1+2log_{5}(x)=log_{5}(16x-3)

1 + 2 lo g_{5} (x) = lo g_{5} (16 x - 3)

x = 3, x = \frac{1}{5}

Decimal Notation

x = 3, x = 0.2

Solution steps

1 + 2 lo g_{5} (x) = lo g_{5} (16 x - 3)

Apply log rules

5 x^{2} = 16 x - 3

Solve

5 x^{2} = 16 x - 3 : x = 3, x = \frac{1}{5}

x = 3, x = \frac{1}{5}

Verify Solutions:

x = 3

True

, x = \frac{1}{5}

True

The solutions are

x = 3, x = \frac{1}{5}

1 = - 2 ln (200 - 0.5 a)

ln (a) = 3.322

lo g_{2} (x) = 3 - lo g_{2} (5)

x, ln (5 - 2 x) = - 7

ln (x) + ln (x - 5) = ln (2 x)

What is the answer to 1+2log_{5}(x)=log_{5}(16x-3) ?
The answer to 1+2log_{5}(x)=log_{5}(16x-3) is x=3,x= 1/5
Solve for x: 1+2log_{5}(x)=log_{5}(16x-3)
The solution is x=3,x= 1/5