What is the answer to 4^2*log_{4}(x+2)=32 ?

The answer to 4^2*log_{4}(x+2)=32 is x=14

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4^2*log_{4}(x+2)=32

4^{2} \cdot lo g_{4} (x + 2) = 32

x = 14

Solution steps

4^{2} lo g_{4} (x + 2) = 32

Divide both sides by

16

lo g_{4} (x + 2) = 2

Apply log rules

x + 2 = 16

Solve

x + 2 = 16 : x = 14

x = 14

Verify Solutions:

x = 14

True

The solution is

x = 14

- 3.5 = 5 lo g_{10} (x) - 5

lo g_{- 2 x - 2} (3 x^{2} - 4 x - 16) = 2

- \frac{ln ( - 10 ( 0 ) ^{2} - x )}{4} = 0

x, f ln (x) = 1

3 lo g_{2} (x) = - lo g_{2} (2 x + 1)

What is the answer to 4^2*log_{4}(x+2)=32 ?
The answer to 4^2*log_{4}(x+2)=32 is x=14
Solve for x: 4^2*log_{4}(x+2)=32
The solution is x=14