What is the answer to log_{5}(x^2)=3.1 ?

The answer to log_{5}(x^2)=3.1 is x=sqrt(5^{3.1)},x=-sqrt(5^{3.1)}

Solve for x: log_{5}(x^2)=3.1

The solution is x=sqrt(5^{3.1)},x=-sqrt(5^{3.1)}

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lo g_{5} (x^{2}) = 3.1

x = 5^{3.1}, x = - 5^{3.1}

Decimal Notation

x = 12.11723 \dots, x = - 12.11723 \dots

Solution steps

lo g_{5} (x^{2}) = 3.1

Apply log rules

x^{2} = 5^{3.1}

Solve

x^{2} = 5^{3.1} : x = 5^{3.1}, x = - 5^{3.1}

x = 5^{3.1}, x = - 5^{3.1}

lo g_{x + 1} (64) = 2

ln (x) = 10.09876582

ln (x) = \frac{1}{e}

ln (x^{6}) - ln (x^{2}) = 4

lo g_{3} ((x + 4)^{2}) = 2

What is the answer to log_{5}(x^2)=3.1 ?
The answer to log_{5}(x^2)=3.1 is x=sqrt(5^{3.1)},x=-sqrt(5^{3.1)}
Solve for x: log_{5}(x^2)=3.1
The solution is x=sqrt(5^{3.1)},x=-sqrt(5^{3.1)}