What is the answer to x/4 =log_{2}(x) ?

The answer to x/4 =log_{2}(x) is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))

Solve for x: x/4 =log_{2}(x)

The solution is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))

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\frac{x}{4} = lo g_{2} (x)

x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

Decimal Notation

x = 16, x = 1.23962 \dots

Solution steps

\frac{x}{4} = lo g_{2} (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{\frac{x}{4}} = 2^{l o g_{2} (x)}

Simplify

2^{l o g_{2} (x)} : x

2^{\frac{x}{4}} = x

Solve

2^{\frac{x}{4}} = x : x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

Verify Solutions:

x = 16

True

, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

True

The solutions are

x = 16, x = - \frac{4 W _{0} ( - \frac{l n ( 2 )}{4} )}{ln ( 2 )}

x, 0.3 = - lo g_{10} (x)

ln (4 x - 3) = ln (9) - ln (x - 3)

lo g_{3} (x + 1) = lo g_{3} (x - 1)

x, y = - ln (x)

lo g_{2} (6 x - 3) = 3

What is the answer to x/4 =log_{2}(x) ?
The answer to x/4 =log_{2}(x) is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))
Solve for x: x/4 =log_{2}(x)
The solution is x=16,x=-(4\W_{0}(-(ln(2))/4))/(ln(2))