What is the answer to 8=4log_{10}((t-2)/(20)) ?

The answer to 8=4log_{10}((t-2)/(20)) is t=2002

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8=4log_{10}((t-2)/(20))

8 = 4 lo g_{10} (\frac{t - 2}{20})

t = 2002

Solution steps

8 = 4 lo g_{10} (\frac{t - 2}{20})

Switch sides

4 lo g_{10} (\frac{t - 2}{20}) = 8

Divide both sides by

4

lo g_{10} (\frac{t - 2}{20}) = 2

Apply log rules

\frac{t - 2}{20} = 1 0^{2}

Multiply both sides by

20

\frac{t - 2}{20} \cdot 20 = 1 0^{2} \cdot 20

Simplify

t - 2 = 2000

Solve

t - 2 = 2000 : t = 2002

t = 2002

Verify Solutions:

t = 2002

True

The solution is

t = 2002

lo g_{2} (x - 1) - lo g_{2} (x + 2) = 1

\frac{1}{2} = lo g_{x} (2)

lo g_{100} (x) = 1.5

lo g_{\frac{1}{4}} (x) = 0

lo g_{\frac{1}{4}} (x) = 1

What is the answer to 8=4log_{10}((t-2)/(20)) ?
The answer to 8=4log_{10}((t-2)/(20)) is t=2002
Solve for t: 8=4log_{10}((t-2)/(20))
The solution is t=2002