What is (2^2x^{-2})/(y^{-2)} ?

The solution to (2^2x^{-2})/(y^{-2)} is (4y^2)/(x^2)

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simplify (2^2x^{-2})/(y^{-2)}

simplify

\frac{2 ^{2} x ^{- 2}}{y ^{- 2}}

\frac{4 y ^{2}}{x ^{2}}

Solution steps

\frac{2 ^{2} x ^{- 2}}{y ^{- 2}}

Simplify

2^{2} x^{- 2} : \frac{4}{x ^{2}}

= \frac{\frac{4}{x ^{2}}}{y ^{- 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{4}{x ^{2} y ^{- 2}}

Simplify

x^{2} y^{- 2} : \frac{x ^{2}}{y ^{2}}

= \frac{4}{\frac{x ^{2}}{y ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{4 y ^{2}}{x ^{2}}

(8 x + 1)^{2} - (7 x - 5)^{2}

(x + 3) (x - 1) < (x - 1)^{2} + 3 x

e^{2 t} + e^{2 t} + 2 t^{2}

0.75 (8 + e) = 2 - 1.25 e

- 5 x + 12 = 5 x - 5

What is (2^2x^{-2})/(y^{-2)} ?
The solution to (2^2x^{-2})/(y^{-2)} is (4y^2)/(x^2)