What is the answer to log_{2}(x+2)=3+log_{2}(1-x) ?

The answer to log_{2}(x+2)=3+log_{2}(1-x) is x= 2/3

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log_{2}(x+2)=3+log_{2}(1-x)

lo g_{2} (x + 2) = 3 + lo g_{2} (1 - x)

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

lo g_{2} (x + 2) = 3 + lo g_{2} (1 - x)

Apply log rules

x + 2 = 8 (1 - x)

Solve

x + 2 = 8 (1 - x) : x = \frac{2}{3}

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

ln (t) = 1.56 + 0.82 \cdot ln (34)

2 lo g_{10} (x) - lo g_{10} (5 x) = 1

x 4 ln (x) - 8 = 12

x - 8 + lo g_{2} (x + 6) = - 5

ln (2 x^{2} - 3) = ln (9 x - 3)

What is the answer to log_{2}(x+2)=3+log_{2}(1-x) ?
The answer to log_{2}(x+2)=3+log_{2}(1-x) is x= 2/3
Solve for x: log_{2}(x+2)=3+log_{2}(1-x)
The solution is x= 2/3