What is the answer to log_{10}(1+x)(0.1)=72 ?

The answer to log_{10}(1+x)(0.1)=72 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(1+x)(0.1)=72

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (1 + x) (0.1) = 72

No Solution for x \in R

Solution steps

lo g_{10} (1 + x) (0.1) = 72

Divide both sides by

0.1

lo g_{10} (1 + x) = 720

Apply log rules

1 + x = 1 0^{720}

Solve

1 + x = 1 0^{720} : x = 1 0^{720} - 1

x = 1 0^{720} - 1

Verify Solutions:

x = 1 0^{720} - 1

False

The solution is

No Solution for x \in R

0 = 3 + lo g_{0.3} (x + 5)

2 lo g_{10} (x) - lo g_{10} (x - 1) = 1

lo g_{e} (x^{2} - 2 x - 2) = 0

ln (\frac{x}{5}) = 4.44

6 = lo g_{2} (5 - 3 x)

What is the answer to log_{10}(1+x)(0.1)=72 ?
The answer to log_{10}(1+x)(0.1)=72 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(1+x)(0.1)=72
The solution is No Solution for x\in\mathbb{R}