What is the answer to log_{2}(-4x^2+12x)=3 ?

The answer to log_{2}(-4x^2+12x)=3 is x=1,x=2

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log_{2}(-4x^2+12x)=3

lo g_{2} (- 4 x^{2} + 12 x) = 3

x = 1, x = 2

Solution steps

lo g_{2} (- 4 x^{2} + 12 x) = 3

Apply log rules

- 4 x^{2} + 12 x = 8

Solve

- 4 x^{2} + 12 x = 8 : x = 1, x = 2

x = 1, x = 2

0.21 = 0.0592 ln (x)

lo g_{4} (y) - lo g_{4} (9) = 3

x = ln (x) + 6

x = ln (x) + 1

5 = 50.238 ln (x) - 314.32

What is the answer to log_{2}(-4x^2+12x)=3 ?
The answer to log_{2}(-4x^2+12x)=3 is x=1,x=2
Solve for x: log_{2}(-4x^2+12x)=3
The solution is x=1,x=2