What is the answer to log_{2}(9x+2)-log_{2}(x-5)=3 ?

The answer to log_{2}(9x+2)-log_{2}(x-5)=3 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(9x+2)-log_{2}(x-5)=3

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (9 x + 2) - lo g_{2} (x - 5) = 3

No Solution for x \in R

Solution steps

lo g_{2} (9 x + 2) - lo g_{2} (x - 5) = 3

Add

lo g_{2} (x - 5)

to both sides

lo g_{2} (9 x + 2) - lo g_{2} (x - 5) + lo g_{2} (x - 5) = 3 + lo g_{2} (x - 5)

Simplify

lo g_{2} (9 x + 2) = 3 + lo g_{2} (x - 5)

Apply log rules

9 x + 2 = 8 (x - 5)

Solve

9 x + 2 = 8 (x - 5) : x = - 42

x = - 42

Verify Solutions:

x = - 42

False

The solution is

No Solution for x \in R

ln (x + 50) = 2

ln (x + 2) - ln (4) = 3

4 ln (x - e) = 4

x, lo g_{x + 1} (y) = 2

\frac{1}{x} = \frac{ln ( x ) + x}{x}

What is the answer to log_{2}(9x+2)-log_{2}(x-5)=3 ?
The answer to log_{2}(9x+2)-log_{2}(x-5)=3 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(9x+2)-log_{2}(x-5)=3
The solution is No Solution for x\in\mathbb{R}