What are the solutions to the equation s^2+10s+37=0 ?

The solutions to the equation s^2+10s+37=0 are s=-5+2sqrt(3)i,s=-5-2sqrt(3)i

Find the zeros of s^2+10s+37=0

The zeros of s^2+10s+37=0 are s=-5+2sqrt(3)i,s=-5-2sqrt(3)i

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s^{2} + 10 s + 37 = 0

s = - 5 + 23 i, s = - 5 - 23 i

Solution steps

s^{2} + 10 s + 37 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 37 : 43 i

s_{1, 2} = \frac{- 10 \pm 4 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 10 + 4 3 i}{2 \cdot 1}, s_{2} = \frac{- 10 - 4 3 i}{2 \cdot 1}

s = \frac{- 10 + 4 3 i}{2 \cdot 1} : - 5 + 23 i

s = \frac{- 10 - 4 3 i}{2 \cdot 1} : - 5 - 23 i

The solutions to the quadratic equation are:

s = - 5 + 23 i, s = - 5 - 23 i

15 x^{4} \geq 4 x^{2} + 35

16 + \frac{1}{3}

\frac{270 π}{180}

- 11 x^{3} y (- 11 y^{3})

10 - 4 ∣ 2 x - 1 ∣ = 6

What are the solutions to the equation s^2+10s+37=0 ?
The solutions to the equation s^2+10s+37=0 are s=-5+2sqrt(3)i,s=-5-2sqrt(3)i
Find the zeros of s^2+10s+37=0
The zeros of s^2+10s+37=0 are s=-5+2sqrt(3)i,s=-5-2sqrt(3)i