What is the answer to 2log_{3}(2x-3)+2=3 ?

The answer to 2log_{3}(2x-3)+2=3 is x=(sqrt(3)+3)/2

Solve for x: 2log_{3}(2x-3)+2=3

The solution is x=(sqrt(3)+3)/2

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2 lo g_{3} (2 x - 3) + 2 = 3

x = \frac{3 + 3}{2}

Decimal Notation

x = 2.36602 \dots

Solution steps

2 lo g_{3} (2 x - 3) + 2 = 3

Move

2

to the right side

2 lo g_{3} (2 x - 3) = 1

Divide both sides by

2

lo g_{3} (2 x - 3) = \frac{1}{2}

Apply log rules

2 x - 3 = 3

Solve

2 x - 3 = 3 : x = \frac{3 + 3}{2}

x = \frac{3 + 3}{2}

Verify Solutions:

x = \frac{3 + 3}{2}

True

The solution is

x = \frac{3 + 3}{2}

9.1 = 10 lo g_{10} (\frac{4.8}{x})

t, lo g_{5} (t) = u

- 3 lo g_{2} (3) = lo g_{2} (x)

ln (3 x - 16) = 7

lo g_{10} (x) = 875

What is the answer to 2log_{3}(2x-3)+2=3 ?
The answer to 2log_{3}(2x-3)+2=3 is x=(sqrt(3)+3)/2
Solve for x: 2log_{3}(2x-3)+2=3
The solution is x=(sqrt(3)+3)/2