What is the answer to log_{10}(x)+log_{10}(x+8)=2 ?

The answer to log_{10}(x)+log_{10}(x+8)=2 is x=2(sqrt(29)-2)

Solve for x: log_{10}(x)+log_{10}(x+8)=2

The solution is x=2(sqrt(29)-2)

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lo g_{10} (x) + lo g_{10} (x + 8) = 2

x = 2 (29 - 2)

Decimal Notation

x = 6.77032 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 8) = 2

Apply log rules

x (x + 8) = 100

Solve

x (x + 8) = 100 : x = 2 (29 - 2), x = - 2 (2 + 29)

x = 2 (29 - 2), x = - 2 (2 + 29)

Verify Solutions:

x = 2 (29 - 2)

True

, x = - 2 (2 + 29)

False

The solution is

x = 2 (29 - 2)

lo g_{2} (\frac{40}{x}) = 3

lo g_{10} (x) = 2.10083394

lo g_{x} (4) = lo g_{2} (x)

5 lo g_{9} (a) = lo g_{9} (x)

lo g_{x} (3) + lo g_{x} (27) = 2

What is the answer to log_{10}(x)+log_{10}(x+8)=2 ?
The answer to log_{10}(x)+log_{10}(x+8)=2 is x=2(sqrt(29)-2)
Solve for x: log_{10}(x)+log_{10}(x+8)=2
The solution is x=2(sqrt(29)-2)