What is the answer to log_{2}(x+2)=35 ?

The answer to log_{2}(x+2)=35 is x=2^{35}-2

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log_{2}(x+2)=35

lo g_{2} (x + 2) = 35

x = 2^{35} - 2

Solution steps

lo g_{2} (x + 2) = 35

Apply log rules

x + 2 = 2^{35}

Solve

x + 2 = 2^{35} : x = 2^{35} - 2

x = 2^{35} - 2

lo g_{\frac{1}{2}} (2 x - 3) = 0

lo g_{3} (2 x + 3) = 5 - lo g_{3} (x + 6)

10000 - 0 = 2000 ln (\frac{3}{m})

2 lo g_{10} (x) - lo g_{10} (5) = - 2

lo g_{2 - 3 k} (125) = 3

What is the answer to log_{2}(x+2)=35 ?
The answer to log_{2}(x+2)=35 is x=2^{35}-2
Solve for x: log_{2}(x+2)=35
The solution is x=2^{35}-2