What is the answer to log_{3}(4x-5)-log_{3}(x+2)=1 ?

The answer to log_{3}(4x-5)-log_{3}(x+2)=1 is x=11

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log_{3}(4x-5)-log_{3}(x+2)=1

lo g_{3} (4 x - 5) - lo g_{3} (x + 2) = 1

x = 11

Solution steps

lo g_{3} (4 x - 5) - lo g_{3} (x + 2) = 1

Add

lo g_{3} (x + 2)

to both sides

lo g_{3} (4 x - 5) - lo g_{3} (x + 2) + lo g_{3} (x + 2) = 1 + lo g_{3} (x + 2)

Simplify

lo g_{3} (4 x - 5) = 1 + lo g_{3} (x + 2)

Apply log rules

4 x - 5 = 3 (x + 2)

Solve

4 x - 5 = 3 (x + 2) : x = 11

x = 11

Verify Solutions:

x = 11

True

The solution is

x = 11

lo g_{3} (x - 9) = x

- 33.10906 = 10 \cdot lo g_{10} (x)

lo g_{10} (x) = 1812913

11 = lo g_{10} (x)

0.65 = ln (y)

What is the answer to log_{3}(4x-5)-log_{3}(x+2)=1 ?
The answer to log_{3}(4x-5)-log_{3}(x+2)=1 is x=11
Solve for x: log_{3}(4x-5)-log_{3}(x+2)=1
The solution is x=11