What is the answer to log_{2}(x)+log_{2}(x+3)=3 ?

The answer to log_{2}(x)+log_{2}(x+3)=3 is x=(-3+sqrt(41))/2

Solve for x: log_{2}(x)+log_{2}(x+3)=3

The solution is x=(-3+sqrt(41))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x) + lo g_{2} (x + 3) = 3

x = \frac{- 3 + 41}{2}

Decimal Notation

x = 1.70156 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x + 3) = 3

Apply log rules

x (x + 3) = 8

Solve

x (x + 3) = 8 : x = \frac{- 3 + 41}{2}, x = \frac{- 3 - 41}{2}

x = \frac{- 3 + 41}{2}, x = \frac{- 3 - 41}{2}

Verify Solutions:

x = \frac{- 3 + 41}{2}

True

, x = \frac{- 3 - 41}{2}

False

The solution is

x = \frac{- 3 + 41}{2}

x, 3 ln (y) = ln (x)

ln (x) = 29.21034037

x, ln (x - y) + k = ln (z + 1)

lo g_{2} ((2 x + 4)^{7}) = 21

lo g_{3} (3 x + 1) + lo g_{3} (2) = 1

What is the answer to log_{2}(x)+log_{2}(x+3)=3 ?
The answer to log_{2}(x)+log_{2}(x+3)=3 is x=(-3+sqrt(41))/2
Solve for x: log_{2}(x)+log_{2}(x+3)=3
The solution is x=(-3+sqrt(41))/2