What is the answer to log_{10}(4x)+log_{10}(13)=0 ?

The answer to log_{10}(4x)+log_{10}(13)=0 is x= 1/52

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log_{10}(4x)+log_{10}(13)=0

lo g_{10} (4 x) + lo g_{10} (13) = 0

x = \frac{1}{52}

Decimal Notation

x = 0.01923 \dots

Solution steps

lo g_{10} (4 x) + lo g_{10} (13) = 0

Move

lo g_{10} (13)

to the right side

lo g_{10} (4 x) = - lo g_{10} (13)

Apply log rules

4 x = \frac{1}{13}

Solve

4 x = \frac{1}{13} : x = \frac{1}{52}

x = \frac{1}{52}

Verify Solutions:

x = \frac{1}{52}

True

The solution is

x = \frac{1}{52}

y, x = - lo g_{e} (y)

ln (2 x - 1) = ln (3 x)

lo g_{10} (x) = 699

3 ln (x + 2) = - 6

lo g_{6} (n) = n

What is the answer to log_{10}(4x)+log_{10}(13)=0 ?
The answer to log_{10}(4x)+log_{10}(13)=0 is x= 1/52
Solve for x: log_{10}(4x)+log_{10}(13)=0
The solution is x= 1/52