What is the answer to -log_{1/12}(-x)=-3 ?

The answer to -log_{1/12}(-x)=-3 is x=-1/1728

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-log_{1/12}(-x)=-3

- lo g_{\frac{1}{12}} (- x) = - 3

x = - \frac{1}{1728}

Decimal Notation

x = - 0.00057 \dots

Solution steps

- lo g_{\frac{1}{12}} (- x) = - 3

Divide both sides by

- 1

lo g_{\frac{1}{12}} (- x) = 3

Apply log rules

- x = \frac{1}{1728}

Solve

- x = \frac{1}{1728} : x = - \frac{1}{1728}

x = - \frac{1}{1728}

Verify Solutions:

x = - \frac{1}{1728}

True

The solution is

x = - \frac{1}{1728}

8 + ln (x) = 0

6.1 = - lo g_{10} (x)

3 lo g_{2} (x + 3) = 1

lo g_{3} (x + 5) = 1

y, ln (3 - y) = k t + 4

What is the answer to -log_{1/12}(-x)=-3 ?
The answer to -log_{1/12}(-x)=-3 is x=-1/1728
Solve for x: -log_{1/12}(-x)=-3
The solution is x=-1/1728