What are the solutions to the equation 4x^2-30x=12+10x ?

The solutions to the equation 4x^2-30x=12+10x are x=5+2sqrt(7),x=5-2sqrt(7)

Find the zeros of 4x^2-30x=12+10x

The zeros of 4x^2-30x=12+10x are x=5+2sqrt(7),x=5-2sqrt(7)

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4 x^{2} - 30 x = 12 + 10 x

x = 5 + 27, x = 5 - 27

Decimal Notation

x = 10.29150 \dots, x = - 0.29150 \dots

Solution steps

4 x^{2} - 30 x = 12 + 10 x

Move

10 x

to the left side

4 x^{2} - 40 x = 12

Move

12

to the left side

4 x^{2} - 40 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 40)^{2} - 4 \cdot 4 (- 12) = 167

x_{1, 2} = \frac{- ( - 40 ) \pm 16 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 16 7}{2 \cdot 4}, x_{2} = \frac{- ( - 40 ) - 16 7}{2 \cdot 4}

x = \frac{- ( - 40 ) + 16 7}{2 \cdot 4} : 5 + 27

x = \frac{- ( - 40 ) - 16 7}{2 \cdot 4} : 5 - 27

The solutions to the quadratic equation are:

x = 5 + 27, x = 5 - 27

6 x^{2} - 66 x + 144 = 0

4 x - 12 = 8

\frac{x}{16} \geq 1 - \frac{x}{32}

1 + \frac{3}{5}

x^{2} - 4 x y + 3 y^{2}

What are the solutions to the equation 4x^2-30x=12+10x ?
The solutions to the equation 4x^2-30x=12+10x are x=5+2sqrt(7),x=5-2sqrt(7)
Find the zeros of 4x^2-30x=12+10x
The zeros of 4x^2-30x=12+10x are x=5+2sqrt(7),x=5-2sqrt(7)