What is the answer to ln(4x)=ln(2)+6ln(x) ?

The answer to ln(4x)=ln(2)+6ln(x) is x=e^{(ln(2))/5}

Solve for x: ln(4x)=ln(2)+6ln(x)

The solution is x=e^{(ln(2))/5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (4 x) = ln (2) + 6 ln (x)

x = e^{\frac{l n ( 2 )}{5}}

Decimal Notation

x = 1.14869 \dots

Solution steps

ln (4 x) = ln (2) + 6 ln (x)

Apply log rules

x = e^{\frac{l n ( 2 )}{5}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{5}}

True

The solution is

x = e^{\frac{l n ( 2 )}{5}}

x, ln (y) + ln (x) = k

2 + lo g_{3} (3 x + 5) = 4

lo g_{10} (x) = 6.1

lo g_{10} (x) = 6.3

lo g_{10} (x) = 6.4

What is the answer to ln(4x)=ln(2)+6ln(x) ?
The answer to ln(4x)=ln(2)+6ln(x) is x=e^{(ln(2))/5}
Solve for x: ln(4x)=ln(2)+6ln(x)
The solution is x=e^{(ln(2))/5}