What is the answer to 10log_{10}(1+x^2)=0.5 ?

The answer to 10log_{10}(1+x^2)=0.5 is x=sqrt(10^{0.05)-1},x=-sqrt(10^{0.05)-1}

Solve for x: 10log_{10}(1+x^2)=0.5

The solution is x=sqrt(10^{0.05)-1},x=-sqrt(10^{0.05)-1}

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10 lo g_{10} (1 + x^{2}) = 0.5

x = 1 0^{0.05} - 1, x = - 1 0^{0.05} - 1

Decimal Notation

x = 0.34931 \dots, x = - 0.34931 \dots

Solution steps

10 lo g_{10} (1 + x^{2}) = 0.5

Divide both sides by

10

lo g_{10} (1 + x^{2}) = 0.05

Apply log rules

1 + x^{2} = 1 0^{0.05}

Solve

1 + x^{2} = 1 0^{0.05} : x = 1 0^{0.05} - 1, x = - 1 0^{0.05} - 1

x = 1 0^{0.05} - 1, x = - 1 0^{0.05} - 1

Verify Solutions:

x = 1 0^{0.05} - 1

True

, x = - 1 0^{0.05} - 1

True

The solutions are

x = 1 0^{0.05} - 1, x = - 1 0^{0.05} - 1

ln (s) = 74484

lo g_{10} (N) = 2

y, x = lo g_{2} (2 y + 1)

ln (- 4 x + 5) - 5 = - 7

ln (3 x + 11) = 4

What is the answer to 10log_{10}(1+x^2)=0.5 ?
The answer to 10log_{10}(1+x^2)=0.5 is x=sqrt(10^{0.05)-1},x=-sqrt(10^{0.05)-1}
Solve for x: 10log_{10}(1+x^2)=0.5
The solution is x=sqrt(10^{0.05)-1},x=-sqrt(10^{0.05)-1}