What is the answer to ln(-4x-x)+ln(3)=ln(2-x) ?

The answer to ln(-4x-x)+ln(3)=ln(2-x) is x=-1/7

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ln(-4x-x)+ln(3)=ln(2-x)

ln (- 4 x - x) + ln (3) = ln (2 - x)

x = - \frac{1}{7}

Decimal Notation

x = - 0.14285 \dots

Solution steps

ln (- 4 x - x) + ln (3) = ln (2 - x)

Apply log rules

- 15 x = 2 - x

Solve

- 15 x = 2 - x : x = - \frac{1}{7}

x = - \frac{1}{7}

Verify Solutions:

x = - \frac{1}{7}

True

The solution is

x = - \frac{1}{7}

x, ln (3 x - 18) = 6

ln (6 x) + ln (6) = ln (3 x + 6)

3 ln (x + 2) = 9

8 + 3 ln (x) = 2

8 + 3 ln (x) = 4

What is the answer to ln(-4x-x)+ln(3)=ln(2-x) ?
The answer to ln(-4x-x)+ln(3)=ln(2-x) is x=-1/7
Solve for x: ln(-4x-x)+ln(3)=ln(2-x)
The solution is x=-1/7