What is the answer to 0=0.6552ln(x)+948-0.1x+0.2 ?

The answer to 0=0.6552ln(x)+948-0.1x+0.2 is No Solution for x\in\mathbb{R}

Solve for x: 0=0.6552ln(x)+948-0.1x+0.2

The solution is No Solution for x\in\mathbb{R}

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0 = 0.6552 ln (x) + 948 - 0.1 x + 0.2

No Solution for x \in R

Solution steps

0 = 0.6552 ln (x) + 948 - 0.1 x + 0.2

Switch sides

0.6552 ln (x) + 948 - 0.1 x + 0.2 = 0

Group like terms

- 0.1 x + 0.6552 ln (x) + 948 + 0.2 = 0

Add the numbers:

948 + 0.2 = 948.2

0.6552 ln (x) + 948.2 - 0.1 x = 0

Move

0.1 x

to the right side

0.6552 ln (x) + 948.2 = 0.1 x

Move

948.2

to the right side

0.6552 ln (x) = 0.1 x - 948.2

Divide both sides by

0.6552

ln (x) = \frac{0.1 x - 948.2}{0.6552}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{\frac{0.1 x - 948.2}{0.6552}}

Simplify

e^{l n (x)} : x

x = e^{\frac{0.1 x - 948.2}{0.6552}}

Solve

x = e^{\frac{0.1 x - 948.2}{0.6552}} : x = - \frac{0.6552 W ( - \frac{0.1}{0.6552 e ^{\frac{948.2}{0.6552}}} )}{0.1}

x = - \frac{0.6552 W ( - \frac{0.1}{0.6552 e ^{\frac{948.2}{0.6552}}} )}{0.1}

Verify Solutions:

x = - \frac{0.6552 W ( - \frac{0.1}{0.6552 e ^{\frac{948.2}{0.6552}}} )}{0.1}

False

The solution is

No Solution for x \in R

x, 4 = lo g_{3} (x)

0 = b lo g_{c} (a x)

20 lo g_{10} (x) = 3

3 lo g_{7} (x) + lo g_{7} (49) = 8

(0.2) = ln (y)

What is the answer to 0=0.6552ln(x)+948-0.1x+0.2 ?
The answer to 0=0.6552ln(x)+948-0.1x+0.2 is No Solution for x\in\mathbb{R}
Solve for x: 0=0.6552ln(x)+948-0.1x+0.2
The solution is No Solution for x\in\mathbb{R}