What is the answer to 2231/10000 =ln(1+x) ?

The answer to 2231/10000 =ln(1+x) is x=e^{2231/10000}-1

Solve for x: 2231/10000 =ln(1+x)

The solution is x=e^{2231/10000}-1

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\frac{2231}{10000} = ln (1 + x)

x = e^{\frac{2231}{10000}} - 1

Decimal Notation

x = 0.24994 \dots

Solution steps

\frac{2231}{10000} = ln (1 + x)

Apply log rules

e^{\frac{2231}{10000}} = 1 + x

Solve

e^{\frac{2231}{10000}} = 1 + x : x = e^{\frac{2231}{10000}} - 1

x = e^{\frac{2231}{10000}} - 1

x, ln (y) = 6 ln (x)

x, ln (x) = - k \cdot t

lo g_{6} (n) = 2

x, lo g_{2} (- 2 x + 3 p) = 3

lo g_{19} (x) = - 19

What is the answer to 2231/10000 =ln(1+x) ?
The answer to 2231/10000 =ln(1+x) is x=e^{2231/10000}-1
Solve for x: 2231/10000 =ln(1+x)
The solution is x=e^{2231/10000}-1