What is the answer to |x^2-3|=2x ?

The answer to |x^2-3|=2x is x=1\lor x=3

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|x^2-3|=2x

x^{2} - 3 = 2 x

x = 1 or x = 3

Solution steps

x^{2} - 3 = 2 x

Find positive and negative intervals

x \leq - 3, - 3 < x < 3, x \geq 3

Solve the inequality for each interval

No Solution or x = 1 or x = 3

x = 1 or x = 3

- 3 = - ∣ c - 7 ∣ + 1

4 x = 15

2 - \frac{3 n}{m} + \frac{9 n ^{2} - 2 m ^{2}}{m ^{2} + 2 mn}

3 (x - 1) < - 3 (2 - 2 x)

\frac{2}{3} x + \frac{3}{2} x \geq \frac{1}{2}