What is the answer to log_{1/2}(4-2x)+2=0 ?

The answer to log_{1/2}(4-2x)+2=0 is x=0

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log_{1/2}(4-2x)+2=0

lo g_{\frac{1}{2}} (4 - 2 x) + 2 = 0

x = 0

Solution steps

lo g_{\frac{1}{2}} (4 - 2 x) + 2 = 0

Move

2

to the right side

lo g_{\frac{1}{2}} (4 - 2 x) = - 2

Apply log rules

4 - 2 x = 4

Solve

4 - 2 x = 4 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

x, 3.65 = - lo g_{10} (x)

ln (ln (x^{2} + 1)) = 0

x, ln (y) = ln (x) - x + c

ln (x) - 5 = - 3

ln (x) + ln (x + 1) = ln (6)

What is the answer to log_{1/2}(4-2x)+2=0 ?
The answer to log_{1/2}(4-2x)+2=0 is x=0
Solve for x: log_{1/2}(4-2x)+2=0
The solution is x=0