What is the answer to log_{10}(4x+8)=2+log_{10}(3) ?

The answer to log_{10}(4x+8)=2+log_{10}(3) is x=73

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log_{10}(4x+8)=2+log_{10}(3)

lo g_{10} (4 x + 8) = 2 + lo g_{10} (3)

x = 73

Solution steps

lo g_{10} (4 x + 8) = 2 + lo g_{10} (3)

Apply log rules

4 x + 8 = 300

Solve

4 x + 8 = 300 : x = 73

x = 73

ln (3) + ln (6 - x) = 2 ln (x)

0 = \frac{1 - 3 ln ( x )}{x ^{3}}

a = 20 lo g_{10} (x)

lo g_{10} (1 - 3 x) = 2

0.25 = ln (x)

What is the answer to log_{10}(4x+8)=2+log_{10}(3) ?
The answer to log_{10}(4x+8)=2+log_{10}(3) is x=73
Solve for x: log_{10}(4x+8)=2+log_{10}(3)
The solution is x=73