What is the answer to a=log_{2x}(4x^2) ?

The answer to a=log_{2x}(4x^2) is No Solution for x\in\mathbb{R}

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a=log_{2x}(4x^2)

a = lo g_{2 x} (4 x^{2})

No Solution for x \in R

Solution steps

a = lo g_{2 x} (4 x^{2})

Apply log rules

a = \frac{ln ( 4 x ^{2} )}{ln ( 2 x )}

Multiply both sides by

ln (2 x)

a ln (2 x) = \frac{ln ( 4 x ^{2} )}{ln ( 2 x )} ln (2 x)

Simplify

a ln (2 x) = ln (4 x^{2})

Apply log rules

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

False

The solution is

No Solution for x \in R

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What is the answer to a=log_{2x}(4x^2) ?
The answer to a=log_{2x}(4x^2) is No Solution for x\in\mathbb{R}