What is the answer to log_{4}(x+3)-log_{4}(x)=1 ?

The answer to log_{4}(x+3)-log_{4}(x)=1 is x=1

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log_{4}(x+3)-log_{4}(x)=1

lo g_{4} (x + 3) - lo g_{4} (x) = 1

x = 1

Solution steps

lo g_{4} (x + 3) - lo g_{4} (x) = 1

Add

lo g_{4} (x)

to both sides

lo g_{4} (x + 3) - lo g_{4} (x) + lo g_{4} (x) = 1 + lo g_{4} (x)

Simplify

lo g_{4} (x + 3) = 1 + lo g_{4} (x)

Apply log rules

x + 3 = 4 x

Solve

x + 3 = 4 x : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

y, d = ln (\frac{x}{y})

n, 0 = lo g_{9} (x^{n})

ln (x) + 2 ln (4 x) = ln (6192)

3 ln (7 x - 1) + 4 = 7

5 lo g_{5} (a) = lo g_{5} (x)

What is the answer to log_{4}(x+3)-log_{4}(x)=1 ?
The answer to log_{4}(x+3)-log_{4}(x)=1 is x=1
Solve for x: log_{4}(x+3)-log_{4}(x)=1
The solution is x=1