What is the answer to 5ln(4x+3)-1=19 ?

The answer to 5ln(4x+3)-1=19 is x=(e^4-3)/4

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5ln(4x+3)-1=19

5 ln (4 x + 3) - 1 = 19

x = \frac{e ^{4} - 3}{4}

Decimal Notation

x = 12.89953 \dots

Solution steps

5 ln (4 x + 3) - 1 = 19

Move

1

to the right side

5 ln (4 x + 3) = 20

Divide both sides by

5

ln (4 x + 3) = 4

Apply log rules

4 x + 3 = e^{4}

Solve

4 x + 3 = e^{4} : x = \frac{e ^{4} - 3}{4}

x = \frac{e ^{4} - 3}{4}

Verify Solutions:

x = \frac{e ^{4} - 3}{4}

True

The solution is

x = \frac{e ^{4} - 3}{4}

lo g_{10} (p^{- 5}) = 16

lo g_{10} (9 - 5 x) = - 1

ln (2 x^{2} - 3) = ln (9 x - 13)

ln (x) = \frac{1}{4 e ^{2}}

10 \cdot lo g_{10} (x) = 58.9

What is the answer to 5ln(4x+3)-1=19 ?
The answer to 5ln(4x+3)-1=19 is x=(e^4-3)/4
Solve for x: 5ln(4x+3)-1=19
The solution is x=(e^4-3)/4