What is the answer to log_{10}(x^2+1)=-0.7 ?

The answer to log_{10}(x^2+1)=-0.7 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x^2+1)=-0.7

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (x^{2} + 1) = - 0.7

No Solution for x \in R

Solution steps

lo g_{10} (x^{2} + 1) = - 0.7

Apply log rules

x^{2} + 1 = \frac{1}{1 0 ^{0.7}}

Solve

x^{2} + 1 = \frac{1}{1 0 ^{0.7}} :

No Solution for

x \in R

No Solution for x \in R

5.56 = ln (\frac{x}{100})

lo g_{10} (x - 2) = \frac{11}{5}

lo g_{7} (\frac{3 x + 2}{x - 2}) = 1

lo g_{3} (6 x - 9) = 4

x, lo g_{3} (x - 1) = 2

What is the answer to log_{10}(x^2+1)=-0.7 ?
The answer to log_{10}(x^2+1)=-0.7 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x^2+1)=-0.7
The solution is No Solution for x\in\mathbb{R}