What is the answer to log_{10}(2x)+2log_{10}(x)=4 ?

The answer to log_{10}(2x)+2log_{10}(x)=4 is x=10^{(4-log_{10}(2))/3}

Solve for x: log_{10}(2x)+2log_{10}(x)=4

The solution is x=10^{(4-log_{10}(2))/3}

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lo g_{10} (2 x) + 2 lo g_{10} (x) = 4

x = 1 0^{\frac{4 - l o g _{10} ( 2 )}{3}}

Decimal

x = 17.09975 \dots

Solution steps

lo g_{10} (2 x) + 2 lo g_{10} (x) = 4

Apply log rules

x = 1 0^{\frac{4 - l o g _{10} ( 2 )}{3}}

Verify Solutions:

x = 1 0^{\frac{4 - l o g _{10} ( 2 )}{3}}

True

The solution is

x = 1 0^{\frac{4 - l o g _{10} ( 2 )}{3}}

lo g_{10} (5 x - 10) = 5

P, lo g_{10} (P^{- 1}) = n

3 lo g_{3} (x - 5) = 3

2 ln (x^{3}) - 3 ln (x^{2}) = 0

2 ln (x - 1) - 2 ln (x + 2) = 2 ln (2)

What is the answer to log_{10}(2x)+2log_{10}(x)=4 ?
The answer to log_{10}(2x)+2log_{10}(x)=4 is x=10^{(4-log_{10}(2))/3}
Solve for x: log_{10}(2x)+2log_{10}(x)=4
The solution is x=10^{(4-log_{10}(2))/3}