What is the answer to log_{2}(3-x)+log_{2}(7-x)=5 ?

The answer to log_{2}(3-x)+log_{2}(7-x)=5 is x=-1

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log_{2}(3-x)+log_{2}(7-x)=5

lo g_{2} (3 - x) + lo g_{2} (7 - x) = 5

x = - 1

Solution steps

lo g_{2} (3 - x) + lo g_{2} (7 - x) = 5

Apply log rules

(3 - x) (7 - x) = 32

Solve

(3 - x) (7 - x) = 32 : x = 11, x = - 1

x = 11, x = - 1

Verify Solutions:

x = 11

False

, x = - 1

True

The solution is

x = - 1

lo g_{2} (2 x + 6) = 3

2 + 2 ln (x) = ln (x) + ln (2)

9 = 9.6 + lo g_{10} (x)

lo g_{2} (x + 2) = lo g_{2} (3 x)

lo g_{x} (x - 2) = 2

What is the answer to log_{2}(3-x)+log_{2}(7-x)=5 ?
The answer to log_{2}(3-x)+log_{2}(7-x)=5 is x=-1
Solve for x: log_{2}(3-x)+log_{2}(7-x)=5
The solution is x=-1