What is the answer to ln(x+4)+ln(x+5)=1 ?

The answer to ln(x+4)+ln(x+5)=1 is x=(-9+sqrt(4e+1))/2

Solve for x: ln(x+4)+ln(x+5)=1

The solution is x=(-9+sqrt(4e+1))/2

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ln (x + 4) + ln (x + 5) = 1

x = \frac{- 9 + 4 e + 1}{2}

Decimal Notation

x = - 2.77712 \dots

Solution steps

ln (x + 4) + ln (x + 5) = 1

Apply log rules

(x + 4) (x + 5) = e

Solve

(x + 4) (x + 5) = e : x = \frac{- 9 + 4 e + 1}{2}, x = \frac{- 9 - 4 e + 1}{2}

x = \frac{- 9 + 4 e + 1}{2}, x = \frac{- 9 - 4 e + 1}{2}

Verify Solutions:

x = \frac{- 9 + 4 e + 1}{2}

True

, x = \frac{- 9 - 4 e + 1}{2}

False

The solution is

x = \frac{- 9 + 4 e + 1}{2}

ln (8 - 8 x) = - 3

4 lo g_{10} (x) = 10

lo g_{10} (z + j) = 0

10 \cdot lo g_{10} (x) = 75

- 8 = 2 + ln (x - 1)

What is the answer to ln(x+4)+ln(x+5)=1 ?
The answer to ln(x+4)+ln(x+5)=1 is x=(-9+sqrt(4e+1))/2
Solve for x: ln(x+4)+ln(x+5)=1
The solution is x=(-9+sqrt(4e+1))/2