What is the answer to 2log_{2}(x-8)+log_{2}(8)=5 ?

The answer to 2log_{2}(x-8)+log_{2}(8)=5 is x=10

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2log_{2}(x-8)+log_{2}(8)=5

2 lo g_{2} (x - 8) + lo g_{2} (8) = 5

x = 10

Solution steps

2 lo g_{2} (x - 8) + lo g_{2} (8) = 5

Move

lo g_{2} (8)

to the right side

2 lo g_{2} (x - 8) = 5 - lo g_{2} (8)

Divide both sides by

2

lo g_{2} (x - 8) = \frac{5 - lo g _{2} ( 8 )}{2}

Apply log rules

x - 8 = 2

Solve

x - 8 = 2 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

ln (x + 2) = 1 + ln (x)

ln (x) = x - 3

lo g_{e} (x - 1) - 1 = 0

4 lo g_{9} (x) - 9 lo g_{27} (7) = 14

5 = \frac{lo g _{10} ( x )}{3} + 3

What is the answer to 2log_{2}(x-8)+log_{2}(8)=5 ?
The answer to 2log_{2}(x-8)+log_{2}(8)=5 is x=10
Solve for x: 2log_{2}(x-8)+log_{2}(8)=5
The solution is x=10