What is the answer to 4log_{10}(x-1)(2x-1)=0 ?

The answer to 4log_{10}(x-1)(2x-1)=0 is x=2

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4log_{10}(x-1)(2x-1)=0

4 lo g_{10} (x - 1) (2 x - 1) = 0

x = 2

Solution steps

4 lo g_{10} (x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

lo g_{10} (x - 1) = 0 or 2 x - 1 = 0

Solve

lo g_{10} (x - 1) = 0 : x = 2

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Verify Solutions:

x = 2

True

, x = \frac{1}{2}

False

The solution is

x = 2

lo g_{10} (x) = 12.449

4 lo g_{10} (x) = lo g_{10} (x^{4})

lo g_{5} (5 x - 3) = lo g_{5} (7 x - 5)

2 lo g_{3} (x) - lo g_{3} (25) = 2

5 = 9.95593 ln (x) + 68.691

What is the answer to 4log_{10}(x-1)(2x-1)=0 ?
The answer to 4log_{10}(x-1)(2x-1)=0 is x=2
Solve for x: 4log_{10}(x-1)(2x-1)=0
The solution is x=2