What is the answer to log_{10}(2x-5)=-1 ?

The answer to log_{10}(2x-5)=-1 is x= 51/20

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log_{10}(2x-5)=-1

lo g_{10} (2 x - 5) = - 1

x = \frac{51}{20}

Decimal Notation

x = 2.55

Solution steps

lo g_{10} (2 x - 5) = - 1

Apply log rules

2 x - 5 = \frac{1}{10}

Solve

2 x - 5 = \frac{1}{10} : x = \frac{51}{20}

x = \frac{51}{20}

lo g_{9} (4 x + 4) = 2

lo g_{2} (x) - 1 = 3

x, y^{2} = ln (x y)

0.78175 = 0.6446 ln (x) - 0.5557

ln (x - 2) = 1

What is the answer to log_{10}(2x-5)=-1 ?
The answer to log_{10}(2x-5)=-1 is x= 51/20
Solve for x: log_{10}(2x-5)=-1
The solution is x= 51/20